6n^2+17=1367

Solution for 6n^2+17=1367 equation:

6n^2+17=1367

We move all terms to the left:

6n^2+17-(1367)=0

We add all the numbers together, and all the variables

6n^2-1350=0

a = 6; b = 0; c = -1350;
Δ = b2-4ac
Δ = 02-4·6·(-1350)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*6}=\frac{-180}{12}
=-15
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*6}=\frac{180}{12}
=15
$